listen buddy,
dimensions refers to it's lengths and widths and all that good jazz
you seen to have formed a good formula for length and you understand that the formal for area is l•w.
so I'll help you find w when the area is 20 squared feet
(2w+3)•w=20
rewrite this as
w(2w+3) and rewrite it further into
2w²+3w you get this by multiplying w by everything in the parentheses
I'm sorry but the only way I can go further is by bringing in something you might conceive as complicated. I'll try to explain as simply as possible
ax²+bx+c is equal to 2w²+3w= 20 when you move the 20 to the other side through subtraction.
so it would look like this 2w²+3w+(-20)=0
check this out my boi, you can find w by using this formula [tex]x = ( - b \binom{ + }{ - } \sqrt{b {}^{2} } - 4ac) \div 2a[/tex]
so -3±✓3²-4(2)(-20) goes first and then will be divided by 2(2)
simplify as -3±✓9+160 and 2(2) as 4
simplify further as (-3±✓169)÷4
the square root of 169 is 13, I suggest you memorize as many square roots as possible because it really helps.
anyways, because of (±) there will be two solutions.
separate them by having two different equations
(-3-13)÷4 and (-3+13)÷4
-3-13=-16, -16÷4=-4
-3+13=10, 10÷4 isn't possible but you can simplify it into 5/2
your solutions for w are -4 and 5/2, but you have to take into consideration that there is no such thing as negative # inches. so use the positive. provide proof by substituting it into the original equation of (2w+3)•w
2•5/2+3= 8, 8• 5/2= 20. I'm sorry I'm really bad at explaining);
