Answer:
[tex] \frac{1}{2} m 8 v^{2} [/tex]
Explanation:
Let initial mass of the moving car is m it is moving with the speed of v m/s.
Thus, Kinetic energy of the car is given by,
Initial Kinetic energy = [tex] \frac{1}{2} m v^{2} [/tex]
Now the velocity of moving car is changed to 3v where as its mass remains the same.
Thus, Kinetic energy of the car is given by,
Final Kinetic energy = [tex] \frac{1}{2} m (3v)^{2} [/tex]
Final Kinetic energy = [tex] \frac{1}{2} m 9 v^{2} [/tex]
The change in kinetic energy is given by,
Change in kinetic energy
= Final kinetic energy - initial kinetic energy
= [tex] \frac{1}{2} m 9 v^{2} [/tex]- [tex] \frac{1}{2} m v^{2} [/tex]
= [tex] \frac{1}{2} m 8 v^{2} [/tex]
Thus, when the speed of a moving car is tripled, kinetic energy is
[tex] \frac{1}{2} m 8 v^{2} [/tex]
