Please help me right away with both problems.
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3) aₓ = 3x + 2
Plug in numbers for x (for example, 1,2,3,4).
a₁ = 3(1) + 2; a₁ = 3 + 2; a₁ = 5
a₂ = 3(2) + 2; a₂ = 6 + 2; a₂ = 8
a₃ = 3(3) + 2; a₃ = 9 + 2; a₃ = 11
a₄ = 3(4) + 2; a₄ = 12 + 2; a₄ = 14
5, 8, 11, 14, or (C) is your answer
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4) 23, 17, 11, 5
Plug in the following numbers to the equations until they match.
C) tₐ = 29 - 6n
when n = 1:
tₐ = 29 - 6(1) ; tₐ = 29 - 6 ; tₐ = 23
tₐ = 29 - 6(2) ; tₐ = 29 - 12 ; tₐ = 17
etc.
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hope this helps
Problem 3.
Use the positive integers for n in increasing order starting with 1. First use n = 1, then n = 2, then n = 3, etc. Replace n with an integer, and solve for an.
[tex] a_n = 3n + 2 [/tex]
[tex] a_1 = 3(1) + 2 = 3 + 2 = 5 [/tex]
[tex] a_2 = 3(2) + 2 = 6 + 2 = 8 [/tex]
[tex] a_1 = 3(3) + 2 = 9 + 2 = 11 [/tex]
[tex] a_4 = 3(4) + 2 = 12 + 2 = 14 [/tex]
Answer: 5, 8, 11, 14
Problem 4.
The first number in the sequence is 23. Each term is then 6 less than the previous term.
[tex] t_1 = 23 [/tex]
[tex] t_2 = 23 - 6 \times 1 [/tex]
[tex] t_3 = 23 - 6 \times 2 [/tex]
Start with 29 - 6, then 29 - 12, 29 - 18.
[tex] t_1 = 29 - 6 = 29 - 6 \times 1 [/tex]
[tex] t_2 = 29 - 12 = 29 - 6 \times 2 [/tex]
[tex] t_3 = 29 - 18 = 29 - 6 \times 3 [/tex]
[tex] t_n = 29 - 6n [/tex]
Answer: [tex] t_n = 29 - 6n [/tex]