FIND THE PERIMETER AND THE AREA, if able, please explain

The pentagon's side lengths are all 11 centimeters, making this a regular pentagon.
The perimeter is found by adding all the side lengths together:
[tex] \text{5 sides in a pentagon} [/tex]
[tex] 11 + 11 + 11 + 11 + 11 = 5(11) = \boxed{55} [/tex]
The pentagon's perimeter is 55 centimeters.
The area of a regular pentagon is found with the following formula:
[tex] A = \frac{1}{4} \sqrt{5 + (5 + \sqrt{2})} \times s^2 [/tex]
s represents the side length.
The side length of the pentagon is 11 cm. Plug this value into the formula:
[tex] \frac{1}{4} \sqrt{5 + (5 + \sqrt{2})} \times 11^2 = \boxed{208.18} [/tex]
The area of the pentagon is 208.18 square centimeters.