Respuesta :
Remark
There are 16 results of throwing a coin 4 times.
Answer 4 first.
These are independent events. No matter what the first result or the second or the third result is outcome can only be 1/2 for any given throw. One event does not influence any other.
One
What this means is that it does not matter what else might be true as long as the second event is heads. So you count THTT and HHHH as both being true. If you use your table, I believe there are 8 results where heads is in the second position.
Two
The last position will also contain heats 8 times. Just count them up. Some of them will be duplicated from your first answer. It does not matter. For example, HHHH will appear in both lists.
Three
For Heads in the second AND the last position you should get 4. They are HHHH THHH THTH HHTH
Answers
P(one) = 8/16. You get 8 answers out of 16 to get a heads in position 2.
P(Two) = 8/16. You get 8 answers out of 16 to get a heads in position 4
P(Three) = 4/16. You get 4 answers out of 16 to get a heads in positions 2 and 4
lets see there are 16 possible outcomes below
HHHH HTHH THHH TTHH
HHHT HTHT THHT TTHT
HHTH HTTH THTH TTTH
I think #1 should be HHHH HTHH
HHHT HTHT
HHTH HTTH
HHTT HTTT
But its been awhile just trying to help out