Answer : His acceleration from 5 s to 10 s will be, [tex]0.8m/s^2[/tex]
Solution : Given,
Initial velocity = 3 m/s
Final velocity = 7 m/s
Initial time = 5 s
Final time = 10 s
Acceleration : Acceleration is defined as the rate of change of velocity with respect to the time taken.
Formula used :
[tex]a=\frac{\Delta V}{\Delta t}\\\\a=\frac{V_{final}-V_{initial}}{t_{final}-t_{initial}}[/tex]
where,
a = acceleration
[tex]\Delta V[/tex] = change in velocity
[tex]\Delta t[/tex] = change in time
Now we have to calculate the acceleration from 5 s to 10 s :
Put all the given values in the above formula, we get
[tex]a=\frac{V_{final}-V_{initial}}{t_{final}-t_{initial}}[/tex]
[tex]a=\frac{7m/s-3m/s}{10s-5s}=0.8m/s^2[/tex]
Therefore, his acceleration from 5 s to 10 s will be, [tex]0.8m/s^2[/tex]
