Remember this information:
[tex]\sqrt{\dfrac{a}{b}} = \dfrac{\sqrt{a}}{\sqrt{b}}[/tex]
(Essentially, the square root of a fraction is equal to the square root of the numerator over the square root of the denominator.)
Applying that rule, we find:
[tex]\sqrt{\dfrac{1}{49}} = \dfrac{\sqrt{1}}{\sqrt{49}} = \pm \dfrac{1}{7}[/tex]
The final answer is [tex]\boxed{\pm \dfrac{1}{7}}[/tex].
