Respuesta :

That "double" less than symbol is used to say "much smaller than". It is of course a qualitative symbol, and it has no rigorous definition.

The exercise asks you to verify, numerically, that if you choose a very, very small input, then the approximations are good. Take the first one for example: we claim that if we pick a very small angle, its cosine is almost one. Let's choose [tex] \theta = 0.00001 [/tex]. If we compute its cosine, we have

[tex] \cos(0.00001) = 0.99999999995 [/tex]

So, approximating the result with 1 is a good approximation.

Similarly, in the second example, we claim that for very small angles, the sine of the angle is almost the angle itself: choosing for example [tex] \theta = 0.001[/tex], we have

[tex] \sin(0.00001) = 0.00099999983333\ldots [/tex]

So the output is almost identically to the input.

For the third, we claim that [tex] e^{-x} [/tex] and [tex]1-x [/tex] are almost the same thing if x is very small. So, for example, we pick [tex] x = 0.00001 [/tex] and we have

[tex] e^{-0.00001} = 0.99999000005\ldots[/tex]

whereas

[tex] 1 - 0.00001 = 0.99999 [/tex]

so the two results are almost identical.

You can keep going like this and "prove" all the remaining approximations