What is the area of the given composite figure, using 3.14 for π. Round to the nearest tenth. (*Hint- find the area of the rectangle and semi-circle then add them together)

Question 1 options:

187.9 cm²


356.9 cm²


433.9 cm²


110.9 cm²

What is the area of the given composite figure using 314 for π Round to the nearest tenth Hint find the area of the rectangle and semicircle then add them toget class=

Respuesta :

The area of the rectangular part = 14 x 20 = 280 sq. cm

The area of the half circle = 1/2 (3.14 x 7^2) = 76.9 sq. cm.


Total area = 280 + 76.93 = 356.9 cm^2



Answer:

356.9 cm² is the answer.

Step-by-step explanation:

The area of the figure can be derived by adding the area of the rectangle and the area of half circle or semicircle.

Length of rectangle = 20 cm

Width of rectangle = 14 cm

So, area is = [tex]20\times14=280[/tex] cm square

Now for semicircle, the radius will be = [tex]\frac{14}{2}=7[/tex] cm

The area can be found as : [tex]\frac{1}{2}\pi r^{2}[/tex]

= [tex]\frac{1}{2}(3.14\times7\times7)[/tex]

= 76.93 cm square

Now adding both the areas, we get the complete area of the figure.

Total area = [tex]280+76.93=356.93[/tex] cm square ≈ 356.9 cm square.