Let's assume
number of chickens =c
number of pigs =p
He counted 60 heads
each pig has one head and each chicken has one head
so, we get equation
[tex]1*c+1*p=60[/tex]
[tex]c+p=60[/tex]
He counted 176 legs
Chicken has two legs
pigs has four legs
so, we get equation as
[tex]2*c+4*p=176[/tex]
[tex]2c+4p=176[/tex]
so, we get two equations as
[tex]c+p=60[/tex]
[tex]2c+4p=176[/tex]
we can eliminate any one variable from first equation and plug that in second equations and then we can solve for c and p
solve for c
[tex]c=60-p[/tex]
plug this into second equation
[tex]2(60-p)+4p=176[/tex]
now, we can solve for p
[tex]120-2p+4p=176[/tex]
[tex]2p=176-120[/tex]
[tex]2p=56[/tex]
[tex]p=28[/tex]
now, we can solve for c
[tex]c=60-28[/tex]
[tex]c=32[/tex]
so,
number of chickens are 32
number of pigs are 28...............Answer
