[tex](6y+11)(8y+5)=0\\ \\ (6y+11)=0\\ \\ 6y=-11\\ \\ y=\frac{-11}{6} \\ \\ (8y+5)=0\\ \\ 8y=-5\\ \\ y=\frac{-5}{8}[/tex]
First separate both equations into two separate problems and solve for y.
Final answers:
[tex]y = \frac{-11}{6} and \frac{-5}{8}[/tex]
