We have to find the number of ways an employer send 3 employees to a job fair if she has 11 employees.
This is the problem from combination.
The formula for combination is given by
[tex]^nC_r= \frac{n!}{r!(n-r)!}[/tex]
Here, n= 11, r= 3
Therefore, total number of ways is given by
[tex]^{11}C_3= \frac{11!}{3!(11-3)!}\\
\\
=\frac{11!}{3!8!}\\
\\
=\frac{8!\times 9 \times 10 \times 11}{3!8!}\\
\\
=\frac{9 \times 10 \times 11}{6}\\
\\
=165[/tex]
A is the correct option.
