To calculate the minimum constant acceleration , we use the equation of motion with uniform acceleration,
[tex]v^{2} = u^{2} +2a S[/tex]
Here, v is final velocity, u is initial velocity, a is acceleration and s is distance.
Given [tex]v = 125 \ km/h= \frac{125 \times 10^3 m}{60 \times 60 \ s} =34 .72 \ m/s[/tex] and [tex]s = 271 \ m[/tex].
Substituting these values with u = 0 (because initial velocity is zero) in above equation, we get
[tex](34.72 m/s) ^2 = 0 + 2 a \times 270 m \\\\ a = \frac{(34.72 m/s) ^2}{2 \times 270 m} = 2.23 \ m/s^2[/tex]
Thus, the minimum constant acceleration is [tex]2.23 \ m/s^2[/tex]