Let l,w be the length and width of rectangle
Given l = w+3.
Let the area be A= l*w = (w+3)*w
Also given that (l-3)*(w+4) = A+8
(w+3-3)*(w+4) = (w+3)*w + 8
[tex]w*(w+4) = w^{2} +3w+8[/tex]
[tex]w^{2} +4w = w^{2}+3w+8[/tex]
Subtracting [tex]w^{2}[/tex] and 3w on both sides
[tex]w^{2}+4w-w^{2}-3w = 8[/tex]
w=8 feet
l= w+3 = 8+3 = 11 feet
Hence length of rectangle = 11 feet.