Respuesta :
We know that acceleration is change in velocity by time taken for that change.
In this case velocity change is 3.7 m/s
Time taken for this change = 60 ms = [tex]6 *10^{-3} seconds[/tex]
So acceleration of frog = [tex]\frac{3.7}{60*10^{-3}}[/tex]
= 61.66 m/[tex]s^2[/tex]
So acceleration of frog is 61.66 m/[tex]s^2[/tex]
o it is evident that frog is capable of remarkable accelerations.
The frog's acceleration during the jump is 62 m/s²
Further explanation
Acceleration is rate of change of velocity.
[tex]\large {\boxed {a = \frac{v - u}{t} } }[/tex]
[tex]\large {\boxed {d = \frac{v + u}{2}~t } }[/tex]
a = acceleration ( m/s² )
v = final velocity ( m/s )
u = initial velocity ( m/s )
t = time taken ( s )
d = distance ( m )
Let us now tackle the problem !
Given:
initial speed = u = 0 m/s
final speed = v = 3.7 m/s
time taken = t = 60 ms = 0.06 s
Unknown:
acceleration = a = ?
Solution:
To find the acceleration of th frog, it can be done in the following way:
[tex]a = \frac{v - u}{t}[/tex]
[tex]a = \frac{3.7 - 0}{0.06}[/tex]
[tex]a = \frac{185}{3}[/tex]
[tex]a \approx 62 ~ m/s^2[/tex]
Conclusion:
The frog's acceleration during the jump is 62 m/s²
Learn more
- Velocity of Runner : https://brainly.com/question/3813437
- Kinetic Energy : https://brainly.com/question/692781
- Acceleration : https://brainly.com/question/2283922
- The Speed of Car : https://brainly.com/question/568302
Answer details
Grade: High School
Subject: Physics
Chapter: Kinematics
Keywords: Velocity , Driver , Car , Deceleration , Acceleration , Obstacle , Speed , Time , Rate, Frog , Jump
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