Respuesta :
Hey there!!
TERMS -
Displacement - the shortest distance from the starting to the ending point
Distance - Longest point .
Now, a person walks 3 km to the west and from there to the 2 km east
The diagram would like :
If we take a starting point anywhere, the line or the distance would travel to the left and then from the walker's perspective, we will have to turn east. From our perspective it would be the line going up.
After we have drawn the figure, it would have a base and a leg, remember, this is a right angle triangle
The base = 3 km
The leg = 2 Km
Displacement = hypotenuse
Use the Pythagorean theorem
c² = a² + b²
where c = hypotenuse , a = base , b = leg or the height
c² = ( 3 )² + ( 2 )²
c² = 9 + 4
c² = 13
c = √13
c = 3.6
Hypotenuse = 3.6
Displacement = 3.6 Km
Distance = longest
How do we find it?
add up the sides from the starting point to the destination
= 3 + 2
= 5 KM
Distance = 5 Km
Magnitude of displacement - North-East
Hope my answer helps!
a) The displacement is 1 kilometer westwards.
b) The cyclist had a distance travelled of 5 kilometers.
c) The magnitude of his displacement is 1 kilometer.
a) The Displacement of the Cyclist is the Vector Sum of the two movements, all measured in kilometers. Let suppose that north and east Directions are positive:
[tex]\vec r = \vec r_{1} + \vec r_{2}[/tex] (1)
If we know that [tex]\vec r_{1} = (-3, 0)\,[km][/tex] and [tex]\vec r_{2} = (2, 0)\,[km][/tex], then the displacement of the cyclist is:
[tex]\vec r = (-1, 0)\,[km][/tex]
The displacement is 1 kilometer westwards.
b) The Travelled Distance, in kilometers, is the sum of the Magnitudes of each Vector:
[tex]r = \|\vec v_{1}\| + \|\vec v_{2}\|[/tex] (2)
[tex]r = 5\,km[/tex]
The cyclist had a distance travelled of 5 kilometers.
c) The magnitude of the Displacement is determined by Pythagorean Theorem, that is to say:
[tex]\|\vec r\| = 1\,km[/tex]
The magnitude of his displacement is 1 kilometer.
Please see this related question: https://brainly.com/question/22565268
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