That's already half done, with the common factor of b+c parenthesized for us. We just pull it out and we're done:
[tex]cb(b+c) + (b+c) = (cb + 1)(b+c)[/tex]
Answer:
(b+c)(cb+1)
Step-by-step explanation:
cb(b+c)+(b+c)
factor out the (b+c)
(b+c)[cb+1]
