To calculate the mass of the fuel, we use the formula
[tex]m = V \times \rho[/tex]
Here, m is the mass of fuel, V is the volume of the fuel and its value is [tex]V =302 \ L = 302 \ L \times \frac{10^{3}m L }{L} = 302 \times 10^{3} \ mL[/tex] and [tex]\rho[/tex] is the density and its value of 0.821 g/mL.
Substituting these values in above relation, we get
[tex]m = 302 \times 10^{3} \ mL \times 0.821 g/mL = 247942 g \\\\ m = 247. 94 \ kg[/tex]
Thus, the mass of the fuel 247 .94 kg.
