[tex](0.45 mol BaSO_{4})*(\frac{6.022*10^23 molecules}{mol})*(\frac{1 atom S}{1 molecule BaSO_{4}}) = 2.7*10^{23}[/tex]
Explanation:
According to the mole concept, there are [tex]6.022 \times 10^{23}[/tex] atoms present in one mole.
As it is given that number of moles of [tex]BaSO_{4}[/tex] are 0.45 mol.
Therefore, there is only one atom of sulfur. Hence, calculate atoms of sulfur as follows.
[tex]1 \times 0.45 \times 6.022 \times 10^{23}[/tex] atoms
= [tex]2.709 \times 10^{23}[/tex] atoms
Thus, we can conclude that there are [tex]2.709 \times 10^{23}[/tex] atoms of sulfur in 0.45 mol [tex]BaSO_{4}[/tex].
