Answer:
3
Step-by-step explanation:
The given equation is ,
[tex]\implies \dfrac{ 3}{m+3} - \dfrac{ m}{ 3-m } =\dfrac{m^2+9}{m^2-9} [/tex]
Firstly lets try to simplify the LHS .Wr have ,
[tex]\implies \dfrac{ 3}{(3+m)(3-m)} =\dfrac{m^2+9}{m^2-9} \\\\\implies \dfrac{ 3(3-m)-m(m+3)}{ 3^2-m^2}= \dfrac{m^2+9}{m^2-9} [/tex]
Simplify using identity , we get ,
[tex]\implies \dfrac{ 9-3m -m^2-3m }{ 9-m^2} = \dfrac{m^2+9}{m^2-9} [/tex]
On futher simplyfing we will get a equation as ,
[tex]\implies m^2-6m +9= m^2 -9 \\\\\implies 6m = 18 \\\\\implies \underline{\underline{ x = 3 }}[/tex]
Hence the required answer is 3 .
