Respuesta :

frika

Consider the function [tex]f(x)=\sqrt{x}.[/tex] This function has:

  • the domain [tex]x\in [0,\infty);[/tex]
  • the range [tex]y\in [0,\infty).[/tex]

If the domain of unknown function is [tex][a,\infty),[/tex] then [tex]x\ge a[/tex] or [tex]x-a\ge 0.[/tex] This means that you have [tex]\sqrt{x-a}[/tex] as a part of needed function.

If the range of unknown function is [tex][b,\infty),[/tex] then [tex]y\ge b.[/tex] This means that you have to translate function b units up and then the expression of the function is

[tex]y=\sqrt{x-a}+b.[/tex]

Answer: correct choice is B.