Answer:
C. Triangle ABC is similar to triangle JEL by AA similarity postulate.
Step-by-step explanation:
We have been given 4 triangles. We are asked to find which triangle is similar to triangle ABC.
We know that angles of triangle add up-to 180 degrees.
Let us find measure of angle C as:
[tex]m\angle A+m\angle B+m\angle C=180^{\circ}[/tex]
[tex]50^{\circ}+65^{\circ}+m\angle C=180^{\circ}[/tex]
[tex]115^{\circ}+m\angle C=180^{\circ}[/tex]
[tex]115^{\circ}-115^{\circ}+m\angle C=180^{\circ}-115^{\circ}[/tex]
[tex]m\angle C=65^{\circ}[/tex]
We can see that in triangles ABC and JEL:
[tex]m\angle B=m\angle E=65^{\circ}[/tex]
[tex]m\angle C=m\angle L=65^{\circ}[/tex]
Therefore, triangle ABC is similar to triangle JEL by angle AA similarity postulate and option C is the correct choice.
