Answer:
Acceleration of that planet is 30 [tex]\frac{m}{s^{2} }[/tex].
Given:
initial speed of hammer = 0 [tex]\frac{m}{s}[/tex]
time = 1 s
distance = 15 m
To find:
Acceleration due to gravity = ?
Formula used:
Distance covered by hammer is given by,
s = ut + [tex]\frac{1}{2} a t^{2}[/tex]
s = distance
u = initial speed of hammer
t = time taken by hammer to reach ground
a = acceleration
Solution:
Distance covered by hammer is given by,
s = ut + [tex]\frac{1}{2} a t^{2}[/tex]
s = distance
u = initial speed of hammer
t = time taken by hammer to reach ground
a = acceleration
u = 0
t = 1 s
s = 15 m
a = g
Thus substituting these value in above equation.
15 = 0 + [tex]\frac{1}{2} g 1^{2}[/tex]
g = 15 × 2
g = 30 [tex]\frac{m}{s^{2} }[/tex]
Thus, acceleration of that planet is 30 [tex]\frac{m}{s^{2} }[/tex].
