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an elliptical park is being built in your neighborhood the park is 25 meters long and 40 meters across. if two swings are being placed at the dock of the ellipse how far from the center mist swings be located

Respuesta :

Answer:

a=20

b=12.5

c=15.61

Step-by-step explanation:

FINDING a

This is a horizontal ellipse because the width of the park is more than its length. length of the major axis = 40 meters a = length of the semi-major axis = 1/2 x 40

        = 20

FINDING b

The length of the minor axis is 25 meters.

    b = length of the semi-minor axis

      = 1/2 x 25

FINDING C

We know that a2 − b2 = c2.

So, c2 = 202 −12.52

           = 400 − 156.25

       c2 = 243.75

       c  15.61

The distance is about 15.61 meters.

The distance is about 15.61 meters.

To find the distance between two swings.

What is ellipse?

A regular oval shape, traced by a point moving in a plane so that the sum of its distances from two other points (the foci) is constant, or resulting when a cone is cut by an oblique plane which does not intersect the base. A closed plane curve generated by a point moving in such a way that the sums of its distances from two fixed points is a constant.

Given that:

This is a horizontal ellipse because the width of the park is more than its length.

Length of the major axis=2a

Length of the semi-major axis=2a/2=a

So, length of the major axis = 40 meters

Length of the semi-major axis = 1/2 x 40

                                                   = 20

Length of the minor axis =2b

length of the semi-minor axis=2b/2=b

So, length of the minor axis is 25 meters.

Length of the semi-minor axis = 1/2 x 25

                                                =25/2

So, to find the focus(c).

We know that [tex]c^{2} =a^{2} -b^{2}[/tex]

          [tex]c^{2} = 202-12.52 \\\\c^{2} = 400 - 156.25 \\\\\\\ c^{2} = 243.75\\\\\\c=\sqrt{243.75} \\\\\\c=15.61 m[/tex]

Therefore, the distance is about 15.61 meters.

Learn more about ellipse  here:

https://brainly.com/question/11035181

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