When sodium amide i.e.[tex]NaNH_{2}[/tex] reacts with water i.e. [tex]H_{2}O[/tex] results in the formation of sodium hydroxide i.e. [tex]NaOH[/tex] and ammonia [tex]NH_{3}[/tex].
The chemical reaction is given by:
[tex]NaNH_{2}+H_{2}O\rightarrow NH_{3}+NaOH[/tex]
Now, when ammonia i.e.[tex]NH_{3}[/tex] reacts with water results in the formation of ammonium hydroxide i.e. [tex]NH_{4}OH[/tex]
The chemical reaction is given by:
[tex]NH_{3}+H_{2}O\rightarrow NH_4OH[/tex]
Thus, the products of the above reactions are ammonia and ammonium hydroxide (without sodium ion).
The structures of the products are shown in figure (1): ammonium hydroxide and figure (2) ammonia.
