When car enters a circular path its speed is increasing at rate 5 m/s^2
so this is the tangential acceleration of car
[tex]a_t = 5 m/s^2[/tex]
now at the same time since car is moving along the curved path so it must have centripetal acceleration at the same time
It is given by equation
[tex]a_c = \frac{v^2}{R}[/tex]
[tex]v = 120 km/h = 33.33 m/s[/tex]
[tex]R = 63 m[/tex]
[tex]a_c = \frac{33.33^2}{63}[/tex]
[tex]a_c = 17.64 m/s^2[/tex]
so now the net acceleration of the car is given as
[tex]a = \sqrt{a_c^2 + a_t^2}[/tex]
[tex]a = \sqrt{5^2 + 17.64^2}[/tex]
[tex]a = 18.33 m/s^2[/tex]
