Respuesta :
A solution on which the solvent and solute are present in a single phase after dissolution is called homogeneous phase. Such solution remains uniform throughout.
The given pairs of substances are:
a. [tex]CO and C_{6}H_{14}[/tex]: CO is a polar gas and [tex]C_{6}H_{14}[/tex]is a non polar liquid. Therefore, this solution will not be homogeneous.
b. [tex]NH_{2}CH_{3}and CH_{4}[/tex]: [tex]NH_{2}CH_{3}[/tex]is a polar liquid while methane is a non polar gas. So, this solution will not be homogeneous.
c. [tex]CBr_{4} and SF_{2}[/tex]: [tex]CBr_{4} [/tex]is a non polar solid while [tex]SF_{2}[/tex]is a polar gas. So, they cannot form homogeneous solution.
d. [tex]NF_{3} and SO_{2}[/tex]: [tex]NF_{3}[/tex] and [tex]SO_{2}[/tex] are both gases. So, they form a uniform homogeneous solution. Both can uniformly interact as they both are polar compounds.
Therefore the correct answer will be [tex]NF_{3} and SO_{2}[/tex]
[tex]\boxed{{\text{N}}{{\text{F}}_{\text{3}}}{\text{ and S}}{{\text{O}}_{\text{2}}}}[/tex] is the pair that is most likely to form a homogeneous solution.
Further Explanation:
Homogeneous solution consists of only one phase. It is formed when the substances are completely dissolved in each other. Solubility is the property of any substance that makes it soluble in other substances. It is governed by the principle “like dissolves like”.
CO and [tex]{{\text{C}}_6}{{\text{H}}_{14}}[/tex]
CO is a polar ionic compound whereas [tex]{{\text{C}}_6}{{\text{H}}_{14}}[/tex] is a non-polar hydrocarbon. Both will not dissolve in each other. So a homogeneous solution will not be formed by CO and [tex]{{\text{C}}_6}{{\text{H}}_{14}}[/tex].
[tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{N}}{{\text{H}}_{\text{2}}}[/tex] and [tex]{\text{C}}{{\text{H}}_{\text{4}}}[/tex]
[tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{N}}{{\text{H}}_{\text{2}}}[/tex] is a polar compound due to the high electronegativity of nitrogen. But [tex]{\text{C}}{{\text{H}}_{\text{4}}}[/tex] is a non-polar covalent compound. Both will not dissolve in each other. So a homogeneous solution will not be formed by [tex]{\text{C}}{{\text{H}}_{\text{3}}}{\text{N}}{{\text{H}}_{\text{2}}}[/tex] and [tex]{\text{C}}{{\text{H}}_{\text{4}}}[/tex].
[tex]{\text{CB}}{{\text{r}}_{\text{4}}}[/tex] and [tex]{\text{S}}{{\text{F}}_2}[/tex]
[tex]{\text{CB}}{{\text{r}}_{\text{4}}}[/tex] is a non-polar covalent compound whereas [tex]{\text{S}}{{\text{F}}_2}[/tex] is a polar covalent compound. Both will not dissolve in each other. So a homogeneous solution will not be formed by [tex]{\text{CB}}{{\text{r}}_{\text{4}}}[/tex] and [tex]{\text{S}}{{\text{F}}_2}[/tex].
[tex]{\text{N}}{{\text{F}}_{\text{3}}}[/tex] and [tex]{\text{S}}{{\text{O}}_{\text{2}}}[/tex]
[tex]{\text{N}}{{\text{F}}_{\text{3}}}[/tex] is slightly polar in nature and [tex]{\text{S}}{{\text{O}}_{\text{2}}}[/tex] is also polar in nature. Also, both are gases. So both will dissolve in each other and therefore a homogeneous solution is formed by [tex]{\text{N}}{{\text{F}}_{\text{3}}}[/tex] and [tex]{\text{S}}{{\text{O}}_{\text{2}}}[/tex].
Learn more:
1. Characteristics of a mixture: https://brainly.com/question/1917079
2. Example of physical change: https://brainly.com/question/1119909
Answer details:
Grade: Senior School
Subject: Chemistry
Chapter: Solutions
Keywords: homogeneous solution, NF3, SO2, CH3NH2, CBr4, SF2, CH4, CO, C6H14, polar, non-polar, ionic compound, solubility, like dissolves like, hydrocarbon.
