The two dimensions of aluminum foil are given 13.72 cm and 8.63 cm respectively with mass 3.1 g.
The density of aluminum is [tex]2.7 g/cm^{3}[/tex]. It is defined as mass per unit volume thus, volume of aluminum can be calculated as follows:
[tex]V=\frac{m}{d}[/tex]
Putting the values.
[tex]V=\frac{3.1 g}{2.7 g/cm^{3}}=1.148 cm^{3}[/tex]
The volume of cuboid is [tex]l\times b\times h[/tex], the length and breadth are given, height can be calculated as follows;
[tex]h=\frac{V}{l\times b}[/tex]
Putting the values,
[tex]h=\frac{1.148 cm^{3}}{(13.72 cm)(8.63 cm)}=0.009695 cm[/tex]
Or, approximately 9.7\times 10^{-3}cm
Therefore, thickness of aluminum foil is [tex]9.7\times 10^{-3}cm[/tex]
