An unknown substance has a mass of 12.3 g . When the substance absorbs 1.107×102 J of heat, the temperature of the substance is raised from 25.0 ∘C to 45.0 ∘C . What is the most likely identity of the substance?

Respuesta :

Heat is equal to product of mass, change in temperature and specific heat.

The formula is given by:

[tex]q=\Delta T\times C\times m[/tex]

where,

q = heat

[tex]\Delta T[/tex]= change in temperature that is [tex]45^{o}C-25^{o}C = 20 ^{o}C [/tex]

m = mass of substance

C=  specific heat capacity

Put the values,

[tex]1.107\times 10^{2} J =20 ^{o}C \times C\times 12.3 g [/tex]

[tex]C= \frac{1.107\times 10^{2} J}{20^{o}C\times 12.3 g}[/tex]

[tex]C= \frac{1.107\times 10^{2} J}{246^{o}C g}[/tex]

= [tex]0.0045 \times 10^{2} J/^{o}C g[/tex]

= [tex]0.45 J/^{o}C g[/tex]

Specific heat capacity is equal to [tex]0.45 J/^{o}C g[/tex] and this  value corresponds to element iron.

Thus, the unknown substance is iron.