The area of a telescope lens is 6.679 × 103 mm2.

(a) What is the area in square feet (ft2)? Enter your answer in scientific notation.
(b) If it takes a technician 43.4 s to polish 1.46 × 102 mm2, how long does it take her to polish the entire lens?

Respuesta :

Given:

Area of a telescope lens = 6.679 * [tex]10^{3} mm^{2}[/tex]

a) [tex]1mm^{2}  = 1.076*10^{-5} ft^{2}[/tex]

Area of lens = 6.679 * [tex]10^{3} mm^{2}[/tex]* 1.076*10^{-5} ft^{2}[/tex]

                     = 7.187 * [tex]10^{-2} ft^{2}[/tex]

b) Time taken to polish an area of 1.46 * [tex]10^{2} mm^{2}[/tex] = 43.4 s

Therefore, time taken to polish the entire lens

                   = 43.4 * 6.679 * [tex]10^{3} mm^{2}/ 1.46 * [tex]10^{2} mm^{2}[/tex]

                   = 1985 sec