Respuesta :
[tex]\bf (\stackrel{x_1}{3}~,~\stackrel{y_1}{24})\qquad (\stackrel{x_2}{7}~,~\stackrel{y_2}{56}) \\\\\\ slope = m\implies \cfrac{\stackrel{photographs}{\stackrel{rise}{ y_2- y_1}}}{\stackrel{album~pages}{\stackrel{run}{ x_2- x_1}}}\implies \cfrac{56-24}{7-3}\implies \cfrac{32}{4}\implies \cfrac{\stackrel{photographs}{8}}{\stackrel{album~pages}{1}}[/tex]
[tex]\bf \rule{34em}{0.25pt}\\\\ \cfrac{\stackrel{photographs}{400}}{\stackrel{album~pages}{50}}\implies \cfrac{\stackrel{photographs}{8}}{\stackrel{album~pages}{1}}\leftarrow \textit{50 pages album, hold 400 photos}[/tex]
Option A is correct. a 50-page photo album holds 400 photographs
The slope is used to determine the steepness of a line.
Give the coordinate points (3, 24) and (7, 56)
Since y varies directly with x, we need to get the slope to determine the correct answer:
[tex]Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope = \frac{56-24}{7-3}\\Slope=\frac{32}{4} \\Slope = \frac{8}{1}[/tex]
This shows that for every 8 number photographs, we can have 1 number of pages in an album.
1 page = 8 photographs
For 50 pages
50pages = x
1/50 = 8/x
x = 8×50
x = 400 photograpghs.
Hence we can conclude that a 50-page photo album holds 400 photographs
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