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one number is 7 times a first number. A third number is 100 more then the first number. if the sum of the three numbers is 721 find the numbers.

Respuesta :

Mauve

b=7a

c=a+100

a+b+c=721

a+7a+a+100=721

9a=621

a=69

c=69+100

c=169

69+b+169=721

b+238=721

b=483

The numbers are 69, 483, and 169

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