Explanation:
To solve:
Note that: " 62 [tex]\frac{1}{2}[/tex] lbs. " ;
↔ can be written as: " 62.5 lbs. " .
→ {since:
→ " ([tex]\frac{1}{2}[/tex])" = "(1 * 5) / (2 * 5)" = "([tex]\frac{5}{10}[/tex])" ;
= " 0.5 " (written as a decimal).
→ And as such:
→ " 62 [tex]\frac{1}{2}[/tex] " = " 62 + 0.5 " = " 62.5 " .
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→ Note that "cubic feet" ; or "cubic foot" ;
→ is a measurement of "volume" ; and can be written as: " ft³ " .
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Using a technique known as "dimensional analysis" ; as follows:
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→ 100 lb * [tex]\frac{1 ft^3}{62.5 lb}[/tex] = __?__ ft³
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→ The units of: "lb." cancel out (to " 1 " ) ;
→ {since: "([tex]\frac{lb.}{lb.}[/tex])" = " 1 " .}.
→ And we have:
→ "(
[tex]\frac{100}{62.5}[/tex])"
