Answer:
Original price of the ticket was $57.
Step-by-step explanation:
Four friends buy tickets for two shows.
Let the price of a ticket was $c
Then cost of 4 tickets = $4c
They use a coupon to get the discount = $5 on each ticket
So total discount on 4 tickets = 4×5 = $20
Cost of the tickets after discount = 4c - 20
Cost of the tickets for two consecutive nights = 2(4c - 20)
If they paid total amount = $416 for 8 tickets
Then the equation will be 2(4c - 20) = 416
Now we can solve this equation to get the original price of the ticket.
2(4c - 20) = 416
4c - 20 = 208
4c = 208 + 20
4c = 228
c = [tex]\frac{228}{4}[/tex]
c = $57
Therefore, original price of a ticket was $57.
