Respuesta :
Step by Step Explanation
From the question,
the dimensions of the tank are;
L = 30 cm, way =0.075m and H = 15 cm
The density of water is given as
[tex]D = 1g {cm}^{ - 3} [/tex]
The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
[tex] {cm}^{3} [/tex]
To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres
[tex]1 inch = 2.54 cm[/tex]
This implies that ,
[tex]H=15 inches=15×2.54cm=38.1cm[/tex]
Also,
[tex]100cm=1m[/tex]
This implies that,
[tex]w= \frac{0.075}{100 } = 7.5 \times {10}^{ - 4} cm[/tex]
Now, the volume of water in the tank can hold, can be found from the relation;
[tex]V=L\times W\times H[/tex]
This implies that,
[tex]v = 30cm \times (7.5 \times {10}^{ - 4} )cm \times 38.1cm[/tex]
[tex]v = 0.857 {cm}^{3} \: to \: 3 \: d.p[/tex]
Finally, we can calculate the mass of the water from the relation given;
[tex]D=\frac{M}{V}[/tex]
This in implies that
[tex]1g {cm}^{ - 3} = \frac{m}{0.857 {cm}^{3} } [/tex]
[tex]m = 1g {cm}^{ - 3} \times 0.857 {cm}^{3} [/tex]
[tex]m = 0.857g[/tex]
Hence the fish tank can hold 0.857g water.
From the question,
the dimensions of the tank are;
L = 30 cm, way =0.075m and H = 15 cm
The density of water is given as
[tex]D = 1g {cm}^{ - 3} [/tex]
The unit of density given in the question means that the mass of the water is in grams and the volume should also be in
[tex] {cm}^{3} [/tex]
To find the volume of the water, we first convert the units of dimensions given in inches and metres to centimetres
[tex]1 inch = 2.54 cm[/tex]
This implies that ,
[tex]H=15 inches=15×2.54cm=38.1cm[/tex]
Also,
[tex]100cm=1m[/tex]
This implies that,
[tex]w= \frac{0.075}{100 } = 7.5 \times {10}^{ - 4} cm[/tex]
Now, the volume of water in the tank can hold, can be found from the relation;
[tex]V=L\times W\times H[/tex]
This implies that,
[tex]v = 30cm \times (7.5 \times {10}^{ - 4} )cm \times 38.1cm[/tex]
[tex]v = 0.857 {cm}^{3} \: to \: 3 \: d.p[/tex]
Finally, we can calculate the mass of the water from the relation given;
[tex]D=\frac{M}{V}[/tex]
This in implies that
[tex]1g {cm}^{ - 3} = \frac{m}{0.857 {cm}^{3} } [/tex]
[tex]m = 1g {cm}^{ - 3} \times 0.857 {cm}^{3} [/tex]
[tex]m = 0.857g[/tex]
Hence the fish tank can hold 0.857g water.
Answer:
8572.5 grams of the water will fish tank can hold.
Explanation:
Volume of the fish tank = V
Length of fish tank = l = 30 cm
Width of fish tank = w = 0.075 m = 7.5 cm
1 m = 100 cm
Length of fish tank = h = 15 inches = 38.1 cm
1 inch = 2.54 cm
[tex]V=l\times w\times h=30 cm\times 0.075 cm\times 38.1 cm=85.725 cm^3[/tex]
Volume of fish tank = Volume of water = v = [tex]8572.5 cm^3[/tex]
Mass of water in the tank = m
Density of the water [tex]d= 1 g/cm^3[/tex]
[tex]D=\frac{m}{v}[/tex]
[tex]m=d\times v=1 g/cm^3\times 8572.5 cm^3=8572.5 g[/tex]
8572.5 grams of the water will fish tank can hold.
