ANSWER
The number of lemonade in the can is 4. So we write,
[tex]n(L)=4[/tex]
The number of apple in the can is 3. So we write,
[tex]n(A)=3[/tex]
The number of iced tea in the can is 5. So we write,
[tex]n(I)=5[/tex].
The total number of drinks in the can,
[tex]n(S)=3+4+5=12[/tex].
Probability of selecting a can of an iced tea,
[tex]P(I)=\frac{n(I)}{n(S)}[/tex]
[tex]P(I)=\frac{5}{12}[/tex]
Since he selected the first one and gave it to his friend, the samples space as well as the number of iced tea will reduce by 1.
Probability of selecting a can of an iced tea again is,
[tex]P(I)=\frac{4}{11}[/tex].
Therefore probability of selecting 2 cans of an iced tea is
[tex]P(2 \:cans of\: iced \:tea)=\frac{5}{12} \times \frac{4}{11}[/tex]
[tex]P(2 \:cans of\: iced \:tea)=\frac{20}{132}[/tex]
[tex]P(2 \:cans of\: iced \:tea)=\frac{5}{33}[/tex]
[tex]P(2 \:cans of\: iced \:tea)=0.152 \: \:or \:\:15.12%[/tex].
The correct answer is option C
