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What is the oxidation state of each element in the compound CaSO4? Include + or - in your answers as appropriate.

The oxidation state of calcium is
.

The oxidation state of sulfur is
.

The oxidation state of oxygen is
.

Respuesta :

Answer:- Ca = +2, S = +6 and O = -2

Solution:- There are certain rules for oxidation numbers. As per the rule, oxidation number of alkaline earth metals in their compounds is +2.

Oxidation number of oxygen in it's compounds is -2(except peroxides) and the sum of oxidation numbers of all the elements of a neutral compound is zero.

Since, Ca is +2 and O is -2, the oxidation number of S could easily be calculated for the given compound as:

Let's say the oxidation number of S in [tex]CaSO_4[/tex] is [tex]x[/tex] . Let's make the algebraic equation and solve it.

[tex]2+x+4(-2)=0[/tex]

[tex]2+x-8=0[/tex]

[tex]x-6=0[/tex]

[tex]x=+6[/tex]

Hence. the oxidation number of Ca is +2, O is -2 and S is +6.


Answer:

Ca = +2, S = +6 and O = -2

Explanation:

EDMENTUM