Respuesta :
Answer:
Part A: The function [tex]f(x)[/tex] has greater slope than function [tex]g(x)[/tex]
Part B: [tex]g(x)[/tex] has a greater y-intercept than [tex]f(x)[/tex].
Step-by-step explanation:
Part A:
For finding the slope of [tex]f(x)[/tex], first we need to pick any two order pairs from the given table in form of [tex](x_{1}, y_{1})[/tex] and [tex](x_{2}, y_{2})[/tex] and then use the formula of slope: [tex]m= \frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]
Lets choose two points as [tex](-1, -15)[/tex] and [tex](0, -10)[/tex]
So, [tex]m= \frac{-10-(-15)}{0-(-1)}= \frac{-10+15}{0+1}= 5[/tex]
Thus, the slope of the function [tex]f(x)[/tex] is 5.
Another function is: [tex]g(x)=2x+8[/tex]
The function [tex]g(x)[/tex] is given in standard slope intercept form [tex]y= mx+b[/tex]. So, we will get [tex]m=2[/tex]
Thus, the slope of the function [tex]g(x)[/tex] is 2.
So, the function [tex]f(x)[/tex] has greater slope than function [tex]g(x)[/tex]
Part B:
For function [tex]f(x)[/tex], there is one ordered pair as [tex](0, -10)[/tex]. This point is lying on the y-axis. So, the y-intercept of [tex]f(x)[/tex] is -10.
Now, in [tex]y= mx+b[/tex] form, [tex]'b'[/tex] is represented as the y-intercept. So, for function [tex]g(x)=2x+8[/tex], the value of [tex]'b'[/tex] will be 8.
Thus, the y-intercept of [tex]g(x)[/tex] is 8.
As [tex]8>-10[/tex],
So, [tex]g(x)[/tex] has a greater y-intercept than [tex]f(x)[/tex].