Respuesta :
Q: The recommended daily allowance of selenium in your diet is 6.97x10-7 mole. How many atoms of selenium is this?
Answer:
4.19 × 10¹⁷ Se Atoms
Solution:
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (atoms) contained by 6.97 × 10⁻⁷ moles of Se, we will use following relation,
Moles = Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of Atoms,
Number of Atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting values,
Number of Atoms = 6.97 × 10⁻⁷ mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of Atoms = 4.19 × 10¹⁷ Atoms
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Q: A bracelet containing 0.200 mol metal is 75% gold. How many atoms of gold are in the bracelet?
Answer:
9.033 × 10²² Atoms of Gold
Solution:
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (atoms) contained by 0.200 moles of Au, we will use following relation,
Moles = Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of Atoms,
Number of Atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting values,
Number of Atoms = 0.200 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of Atoms = 1.20 × 10²³ Atoms
For 75%,
Number of Atoms = 1.20 × 10²³ Atoms × 0.75
Number of Atoms = 9.033 × 10²² Atoms of Gold
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Q: Which has more atoms, 10.0 g C or 10.0 g of Ca? How many atoms does each contain?
Answer:
Carbon has greater number of Atoms.
Solution:
Data Given:
Mass of Carbon = 10 g
M.Mass of Carbon = 12.01 g.mol⁻¹
Mass of Calcium = 10 g
M.Mass of Calcium = 40.08 g.mol⁻¹
Step 1: Calculate Moles of Carbon as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 10 g ÷ 12.01 g.mol⁻¹
Moles = 0.8326 mol
Step 2: Calculate number of Carbon atoms,
As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Carbon atoms can be written as,
Moles = Number of C Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of C atoms,
Number of C atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting value of moles,
Number of C atoms = 0.8326 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of C atoms = 5.01 × 10²³ C atoms
Step 3: Calculate Moles of Calcium as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 10 g ÷ 40.08 g.mol⁻¹
Moles = 0.25 mol
Step 4: Calculate number of Calcium atoms,
As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Calcium atoms can be written as,
Moles = Number of Ca Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of Ca atoms,
Number of Ca atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting value of moles,
Number of Ca atoms = 0.25 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of Ca atoms = 1.50 × 10²³ C atoms
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Q: A mixture contains 0.250 mol Fe and 1.20 g C. What is the total number of atoms in the mixture?
Answer:
2.10 × 10²³ Atoms in Mixture
Solution:
Atoms in Fe:
As we know that 1 mole of any substance contains exactly 6.022 × 10²³ particles which is also called as Avogadro's Number. So in order to calculate the number of particles (atoms) contained by 0.25 moles of Fe, we will use following relation,
Moles = Number of Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of Atoms,
Number of Atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Putting values,
Number of Molecules = 0.25 mol × 6.022 × 10²³ Atoms.mol⁻¹
Number of Molecules = 1.50 × 10²³ Atoms of Fe
Atoms in C:
Step 1: Calculate Moles of Carbon as,
Moles = Mass ÷ M.Mass
Putting values,
Moles = 1.20g ÷ 12.01 g.mol⁻¹
Moles = 0.0999 mol
Step 2: Calculate number of Carbon atoms,
As 1 mole of any substance contains 6.022 × 10²³ particles (Avogadro's Number) then the relation for Moles and Number of Carbon atoms can be written as,
Moles = Number of C Atoms ÷ 6.022 × 10²³ Atoms.mol⁻¹
Solving for Number of C atoms,
Number of C atoms = Moles × 6.022 × 10²³ Atoms.mol⁻¹
Number of C atoms = 0.0999 × 6.022 × 10²³ Atoms.mol⁻¹
Number of C atoms = 6.01 × 10²² C Atoms
Total Number of Atoms:
= 6.01 × 10²² C Atoms + 1.50 × 10²³ Atoms of Fe
= 2.10 × 10²³ Atoms in Mixture
Remaining answers are attached.