Respuesta :
[tex]8x^2 +4x-3[/tex] is divided by 2x-1
We use long division
4x +4 ------------> Quotient
----------------------------
2x-1 8x^2 +4x−3
8x^2 - 4x (Subtract it from the top)
---------------------------
+ 8x -3
8x - 4 (Subtract it from the top)
----------------------------------
+1 ------------> Remainder
So , 1 is the remainder.
The remainder is one.. a quick way to do this is by finding what value of 2x-1=0 then sub that into the original equation. In this case sub x=1/2 into 8x^2 + 4x-3 ... this will give you the remainder
