Answer:
A 1,000 kg ball traveling at 5 m/s would have 10 times more kinetic energy.
A 10 kg ball traveling at 5 m/s would have 10 times less kinetic energy.
A 100 kg person falling at 5 m/s would have the same kinetic energy.
Explanation:
Edg 2020
When the mass of the object is 1000 kg and velocity 5 m/s, the change in kinetic energy is 11,250 J.
When the mass of the object is 10 kg and velocity 5 m/s, the change in kinetic energy is -1,125 J.
When the mass of the object is 100 kg and velocity 5 m/s, the change in kinetic energy is 0.
The kinetic energy of an object is the energy possessed by the object due to its motion.
[tex]K.E = \frac{1}{2} mv^2\\\\[/tex]
The kinetic energy of the object with mass, 100 kg and velocity 5 m/s.
[tex]K.E = \frac{1}{2} \times 100\times 5^2 = 1250 \ J[/tex]
When the mass of the object is 1000 kg and velocity 5 m/s, the change in kinetic energy is calculated as follows;
[tex]\Delta K.E = \frac{1}{2} \times 1000 \times 5^2 \ - \ \frac{1}{2} \times 100\times 5^2\\\\\Delta K.E = 11,250 \ J[/tex]
When the mass of the object is 10 kg and velocity 5 m/s, the change in kinetic energy is calculated as follows
[tex]\Delta K.E = \frac{1}{2} \times 10 \times 5^2 \ - \ \frac{1}{2} \times 100\times 5^2\\\\\Delta K.E = -1,125 \ J[/tex]
When the mass of the object is 100 kg and velocity 5 m/s, the change in kinetic energy is calculated as follows
[tex]\Delta K.E = \frac{1}{2} \times 100\times 5^2 \ - \ \frac{1}{2} \times 100\times 5^2\\\\\Delta K.E = 0 \ J[/tex]
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