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The pH of 0.10 M solution of an acid is 6. What is the percentage ionization of the acid?
6.0 %
0.00010%
10%
0.0010%

Respuesta :

Hey there!:

HA <=> H⁺ + A⁻

pH = -log[H+] = 6

[ H⁺ ] = 10^-pH

[ H⁺] = 10 ^ -6

[ H⁺ ] = 0.000001 M

Percent dissociation:

[ H⁺ ] / [ HA]o * 100

[ 0.000001 / 0.10 ] * 100

0.00001 * 100 => 0.0010%

Answer  D

Hope that helps!


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