Answer:
Deceleration of the car is 2[tex]\frac{m}{s^{2} }[/tex].
Explanation:
Given:
initial speed = 12 m/s
final speed = 8 m/s
time = 2 s
To find:
acceleration = ?
Formula used:
According to first kinematic equation:
v = u + a t
Where, v = final speed
u = initial speed
t = time
a = acceleration
Solution:
According to first kinematic equation:
v = u + a t
Where, v = final speed
u = initial speed
t = time
a = acceleration
8 = 12 + 2 a
-4 = 2 a
a = -2 [tex]\frac{m}{s^{2} }[/tex]
The negative sign implies that it is deceleration. Thus, deceleration of the car is 2[tex]\frac{m}{s^{2} }[/tex].
Answer:
Acceleration value of car = -2 [tex]m/s^2[/tex]
Explanation:
We have equation of motion, v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration and t is the time taken.
Here a car is traveling at 12 m/s, so initial velocity = 12 m/s
After 2 seconds the speed drops to 8 m/s, so final velocity = 8 m/s
Time taken = 2 seconds
Substituting
8 = 12 + a * 2
2a = -4
a = -2 [tex]m/s^2[/tex]
Acceleration value of car = -2 [tex]m/s^2[/tex]
