An ice-hockey puck is slid along ice in a straight line. The puck travels at a steady speed of 20 ms^-1 and experiences no frictional force. How far does the puck travel in 2.5 s?

a. 5 m
b. 8 m
c. 25 m
d. 50 m

Respuesta :

Answer:

d. 50 m

Step-by-step explanation:

1. You have the following information given in the problem above:

- The speed of the puck is 20 [tex]\frac{m}{s}[/tex] and experiences no frictional force.

- The time is 2.5 seconds.

2. Then, to calculate the distance, you must apply the following formula:

[tex]d=Vt[/tex]

Where [tex]d[/tex] is the distance, [tex]V[/tex] is the speed and [tex]t[/tex] is the time.

3. Now, you must substitute values into the formula, as below:

[tex]d=(20\frac{m}{s})(2.5s)[/tex]

4. Therefore, the result is:

[tex]d=50m[/tex]