Answer:
Intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction
Step-by-step explanation:
Required vector is consists of the two components
vx= 2+4=6 units and vy= 1 unit and vx ⊥ vy
We will use Pythagorian theorem to find intensity of the vector v
v∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 units
The angle ∡α between vector and east direction we wil find with tanα
tanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°
Good luck!!!
