Jacob drew a regression line for this paired data set

His line passed through (2,10) and (7,18)

What is the equation of Jacobs regression line?

A)y=6.8x+1.6
B)y=1.375x+4.25
C)y=0.625x-4.25
D)y=1.6+6.8

Respuesta :

Answer: [tex]y=1.6x+6.8[/tex]


Step-by-step explanation:

1. The equation of a regression line has the following form:

[tex]y=mx+b[/tex]

Where [tex]m[/tex] is the slope and [tex]b[/tex] is the y-intercept.

2. You need to calculate the slope with the points given in the exercise:

[tex]m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}[/tex]

3. Substitute values:

[tex]m=\frac{18-10}{7-2}[/tex]

[tex]m=\frac{8}{5}=1.6[/tex]

4. Now, you must calculate [tex]b[/tex]:

-Substitute the value of the slope into the equation above.

- Take one of the given points and substitute them into the equation.

Then:

[tex]y=mx+b\\10=(1.6)(2)+b\\b=10-3.2\\b=6.8[/tex]

5. Therefore, the equation is:

[tex]y=1.6x+6.8[/tex]