What is the slope of the line that contains the points (4,8) and (9,8)? What type of line is it?

A. Slope = 0; horizontal line
B. The line has no slope; it's a vertical line.
C. Slope = 0; vertical line
D. The line has no slope; it's a horizontal line.

Respuesta :

it's definitely c.slope =9; vertical line

For this case we have the following:


Given points: [tex](x1, y1) = (4,8)[/tex] and [tex](x2, y2) = (9,8)\\[/tex]

The formula of the slope is given by:


[tex]m = \frac{(y2-y1)}{(x2-x1)}\\\\m = \frac{(8-8)}{(9-4)}\\\\m = \frac{0}{5}\\\\m = 0\\[/tex]

So, the slope is [tex]m = 0[/tex]and the line is a horizontal line


Answer:


Slope 0, horizontal line