The length of a rectangle room is 6 feet longer than twice the width. If the room's perimeter is 132 feet, what are the room's dimensions?

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Answer:

The width of the room is 20 feet.

The Length of the room is  [tex]46[/tex] feet.

Step-by-step explanation:

Lets take the width of the room as [tex]x[/tex] feet

Then the length of the room will be [tex]2x+6[/tex] feet

Perimeter of a room is the addition of all the walls making the boundary of the room.

Perimeter of the rectangular room = 2 * Width + 2 * Length

⇒[tex]132=2*x+2*(2x+6)[/tex]

⇒[tex]132=2x+4x+12[/tex]

⇒[tex]132=6x+12[/tex]

⇒[tex]132-12=6x[/tex]

⇒[tex]120=6x[/tex]

⇒[tex]20=x[/tex]

Therefore,

The width of the room is 20 feet.

The Length of the room is,

[tex]2x+6[/tex] = [tex]2*20+6[/tex] = [tex]46[/tex] feet