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mattttttthhhhhhhhhhhhhh , i need help




Find the equation of a line that goes through the points (0,3), and (−10,4).

a.y=−110x+3

b.y=−10x

c.y=−110x

d.y=−13x

e.y=−10x+3

Respuesta :

gmany

The slope-point formula:

[tex]y-y_1=m(x-x_1)\\\\m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

We have (0, 3) and (-10, 4)

Substitute:

[tex]m=\dfrac{4-3}{-10-0}=\dfrac{1}{-10}\\\\y-3=-\dfrac{1}{10}(x-0)\qquad|\text{add 3 to both sides}\\\\y=-\dfrac{1}{10}x+3\to\boxed{A.}[/tex]

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