Respuesta :

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[tex]2<\sqrt5<3\\\\\text{because}\\\\2^2=4\\(\sqrt5)^2=5\\3^2=9\\\\2^2=4<(\sqrt5)^2=5<3^2=9[/tex]

Integers are positive and negative numbers without decimal points.

The square root of 5 is between 2 and 3

The number is given as:

[tex]\mathbf{n = \sqrt{5}}[/tex]

Evaluate the square root

[tex]\mathbf{n = 2.2361}[/tex]

The above number is greater than 2 but less than 3.

So, we can say that:

2.2361 is between 2 and 3

Hence, the square root of 5 is between 2 and 3

Read more about integers at:

https://brainly.com/question/11337513